From: Steinar H. Gunderson Date: Sun, 21 Oct 2007 12:33:34 +0000 (+0200) Subject: Generalize the Gauss-Jordan solver to arbitrary sizes. In the process it's X-Git-Url: https://git.sesse.net/?p=foosball;a=commitdiff_plain;h=122dbc0df9343cfe2b6246c9993bdf0da3b1cf79 Generalize the Gauss-Jordan solver to arbitrary sizes. In the process it's becoming really crufty old code =) --- diff --git a/foosrank.cpp b/foosrank.cpp index bdb54f2..25298e7 100644 --- a/foosrank.cpp +++ b/foosrank.cpp @@ -177,70 +177,41 @@ static void mat_mul_trans(double *matA, unsigned ah, unsigned aw, } } -// solves Ax = B by Gauss-Jordan elimination, where A is a 3x3 matrix, -// x is a column vector of length 3 and B is a row vector of length 3. +// solves Ax = B by Gauss-Jordan elimination, where A is an NxN matrix, +// x is a column vector of length N and B is a row vector of length N. // Destroys its input in the process. -static void solve3x3(double *A, double *x, double *B) +template +static void solve_matrix(double *A, double *x, double *B) { - // row 1 -= row 0 * (a1/a0) - { - double f = A[1] / A[0]; - A[1] = 0.0; - A[4] -= A[3] * f; - A[7] -= A[6] * f; - - B[1] -= B[0] * f; - } - - // row 2 -= row 0 * (a2/a0) - { - double f = A[2] / A[0]; - A[2] = 0.0; - A[5] -= A[3] * f; - A[8] -= A[6] * f; - - B[2] -= B[0] * f; - } - - // row 2 -= row 1 * (a5/a4) - { - double f = A[5] / A[4]; - A[5] = 0.0; - A[8] -= A[7] * f; - - B[2] -= B[1] * f; - } - - // back substitute: - - // row 1 -= row 2 * (a7/a8) - { - double f = A[7] / A[8]; - A[7] = 0.0; - - B[1] -= B[2] * f; - } - - // row 0 -= row 2 * (a6/a8) - { - double f = A[6] / A[8]; - A[6] = 0.0; + for (int i = 0; i < N; ++i) { + for (int j = i+1; j < N; ++j) { + // row j -= row i * (a[i,j] / a[i,i]) + double f = A[j+i*N] / A[i+i*N]; + + A[j+i*N] = 0.0; + for (int k = i+1; k < N; ++k) { + A[j+k*N] -= A[i+k*N] * f; + } - B[0] -= B[2] * f; + B[j] -= B[i] * f; + } } - // row 0 -= row 1 * (a3/a4) - { - double f = A[3] / A[4]; - A[3] = 0.0; - - B[0] -= B[1] * f; + // back-substitute + for (int i = N; i --> 0; ) { + for (int j = i; j --> 0; ) { + // row j -= row i * (a[j,j] / a[j,i]) + double f = A[i+j*N] / A[j+j*N]; + + // A[j+i*N] = 0.0; + B[j] -= B[i] * f; + } } // normalize - x[0] = B[0] / A[0]; - x[1] = B[1] / A[4]; - x[2] = B[2] / A[8]; + for (int i = 0; i < N; ++i) { + x[i] = B[i] / A[i+i*N]; + } } // Give an OK starting estimate for the least squares, by numerical integration @@ -338,7 +309,7 @@ static void least_squares(vector > &curve, double mu1, doub mat_mul_trans(matA, curve.size(), 3, dbeta, curve.size(), 1, matATdb); // solve - solve3x3(matATA, dlambda, matATdb); + solve_matrix<3>(matATA, dlambda, matATdb); A += dlambda[0]; mu += dlambda[1];