From: Marco Costalba <mcostalba@gmail.com>
Date: Sat, 24 Dec 2011 08:55:35 +0000 (+0100)
Subject: Correctly define operators in types.h
X-Git-Url: https://git.sesse.net/?p=stockfish;a=commitdiff_plain;h=e89a8e0913640d874432bf2ca5b2495b3dcd8f7e;hp=d543a64cc7fc06daed275b332b10ea06ba738001

Correctly define operators in types.h

Be consistent with the way these operators are defined
in plain C (and in C++).

Spotted by Lucas Braesch.

No functional change.

Signed-off-by: Marco Costalba <mcostalba@gmail.com>
---

diff --git a/src/types.h b/src/types.h
index d9efb6e8..ff7cc766 100644
--- a/src/types.h
+++ b/src/types.h
@@ -323,10 +323,10 @@ inline T operator/ (const T d, int i) { return T(int(d) / i); } \
 inline T operator- (const T d) { return T(-int(d)); } \
 inline T operator++ (T& d, int) {d = T(int(d) + 1); return d; } \
 inline T operator-- (T& d, int) { d = T(int(d) - 1); return d; } \
-inline void operator+= (T& d1, const T d2) { d1 = d1 + d2; } \
-inline void operator-= (T& d1, const T d2) { d1 = d1 - d2; } \
-inline void operator*= (T& d, int i) { d = T(int(d) * i); } \
-inline void operator/= (T& d, int i) { d = T(int(d) / i); }
+inline T& operator+= (T& d1, const T d2) { d1 = d1 + d2; return d1; } \
+inline T& operator-= (T& d1, const T d2) { d1 = d1 - d2; return d1; } \
+inline T& operator*= (T& d, int i) { d = T(int(d) * i); return d; } \
+inline T& operator/= (T& d, int i) { d = T(int(d) / i); return d; }
 
 ENABLE_OPERATORS_ON(Value)
 ENABLE_OPERATORS_ON(PieceType)