+ /*
+ * There's a somewhat subtle point here. Normally, what a player would be interested in
+ * with regard to qualification would be a set of three values:
+ *
+ * 1. How much is the absolute minimum required to qualify, given that all others
+ * fail?
+ * 2. How much will give a reasonable chance of qualifying, given the expected performance
+ * of all the others?
+ * 3. How much will be enough to secure qualification, no matter what?
+ *
+ * Given perfect guessing, #2 would be "how much is needed to qualify"; however, it is
+ * completely impossible to give an exact value for that, and we're not into the guessing
+ * games. :-) #1 is often so low it's completely unrealistic (ie. far enough from #2 that
+ * it's not interesting), but #3, the most conservative estimate, is often a good measure.
+ * #3 is "how much is needed to _secure_ qualification", and that is usually what we
+ * print out when it's possible.
+ *
+ * However, in a few situations, #1 and #3 will be the exact same value, from which it
+ * follows (from the squeeze law, or just common sense :-) ) that #2 will be the same
+ * value as #1 and #3. (This usually happens near or at the end of a group.) In that
+ * case, we know the value we seek (ie. "how much is needed to qualify"), so we drop
+ * the word "secure" and just print it as-is.
+ *
+ * To find #1 and #3, we sort and pick out the values we need to beat in the best and
+ * the worst case.
+ */
+ int qualify_beat_worst_case = -1, qualify_beat_best_case = -1;
+
+ if (group.num_qualifying > 0) {
+ std::vector<unsigned> tmp;
+
+ for (unsigned i = 0; i < group.players.size(); ++i) {
+ if (group.players[i].id == next_player->id)
+ continue;
+ tmp.push_back(max_score[i]);
+ }
+ std::sort(tmp.begin(), tmp.end());
+ qualify_beat_worst_case = tmp[tmp.size() - group.num_qualifying];
+
+ std::vector<unsigned> tmp2;
+ for (unsigned i = 0; i < group.players.size(); ++i) {
+ if (group.players[i].id == next_player->id)
+ continue;
+ tmp2.push_back(min_score[i]);
+ }
+
+ std::sort(tmp2.begin(), tmp2.end());
+ qualify_beat_best_case = tmp2[tmp2.size() - group.num_qualifying];
+ }
+